The height of a projectile fired at an initial velocity, V0and an angle, , is a function of time t:
Height (t) = t V0 sin (tita ) – ½ gt2
Where g is the acceleration due to gravity, 9.8 m/s2.
For an initial velocity of 75 m/s, create an appropriately formatted graph of the height of a projectile vs. time for firing angles (in radians) of , , , and . Assume the projectile starts at a height of 20 meters, as if the launcher is on the top of a hill.
Adjust your results so that the height of the projectile cannot go below 0 meters. Once the projectile has fallen back to earth, it cannot to fall.
Solve the above question using MATLAB. All your work must be performed in the M-file.
This question belongs to MATLAB software and discusses about application of MATLAB in physics to solve projectile problems and to determine distance of the projectile.
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