A torpedo boat with a displacement of 60 long tons is moving at 18 knots when it fires at 300-lb torpedo horizontally with the launch tube at the 30° angle shown. If the torpedo bas a velocity relative to the boat of 20 ft/sec as it leaves the tube, determine the momentary reduction âˆ†v in forward speed of the boat. Recall that 1 knot = 1.688 ft/sec and 1 long ton = 2240 lb. Solve the problem also by referring the motion to a coordinate system moving with the initial speed of the boat.
The question belongs to Mechanical Engineering and the question is about calculating the speed of the boat after it launches a torpedo at a 30° angle. The momentary reduction in speed of the boat needs to be calculated. The calculation has been given in the solution in detail.
Note: The answers are in handwritten format
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